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popeye/zulang.out at master · thomas-maeder/popeye · GitHub
github.com
Popeye is a chess problem solving and testing software with strong support for fairy chess and heterodox genres. For more information cf. topic
Bücher
Das Schach-Sammelsurium: Tag für Tag Anekdoten, Kurioses, Kalendarium...
books.google.de
Eine wahre Hommage an das Schachspiel! Dieses Sammelsurium führt auf unterhaltsame Weise durch die faszinierende Welt des Schachs. Ein Kalendarium begleitet...
Artikel & Meinungen
18 Queens Problem - Chess Forums - Page 2 - Chess.com
www.chess.com
in case it matters http://chess.stackexchange.com/a Friedrich Burchard & Friedrich Hariuc (1976) did it in 96 Half-moves. MGleason.
Only Chess : The Chess Problem and HeinzKat
www.dailychess.com
Only Chess forum - The Chess Problem and HeinzKat
Sonstiges
Schwalbe - deutsche Vereinigung für Problemschach e.V.
www.dieschwalbe.de
Willkommen auf der Website der Schwalbe, deutsche Vereinigung für Problemschach e.V.
18 kraliçe ile mümkün olan en kısa oyun?
qastack.info.tr
[Çözüm bulundu!] 96 Half-hamlede Friedrich Burchard & Friedrich Hariuc (1976) tarafından çözüm NN - NN1. e4 f5 2.…
CPUN-volumul-1 - PDFCOFFEE.COMpdfcoffee.com › cpun-volumul-1-pdf-free
pdfcoffee.com
... Gîlea Mihai Grama Constantin Grădinaru Nicolae Grădinaru Alexandru Grigorescu Dorel Haraga Friedrich Hariuc Dan Hăulică Hugo Hausl Decebal Gerghelegiu ...
Găsiți cel mai scurt joc de șah cu 18 regine?
de-vraag.com
Din poziția * poziția de start a unui tabla de șah, trebuie să mutați piesele pentru a ajunge la Queens după regulile de șah în orice moment (aceasta...
Chess Problem Database Server
pdb.dieschwalbe.de
, 21:22:35, hpr, Friedrich Hariuc, refaut, add , 21:22:35, hpr, (C) Die Schwalbe 234A 2008, refsrc, add , 21:22:35, hpr, h#, refgen ...
Julia's Fairiesjuliasfairies.com › problems
juliasfairies.com
original – Dedicated to Friedrich Hariuc. Solutions: (click to show/ hide). hs#3 3 solutions (5+3) Maximummer Sentinelles Pion Advers Super-Circe
Kürzestes Spiel mit 18 Königinnen? - QA Stackqastack.com.de › chess › shortest-possible-game-with-18-queens
qastack.com.de
[Lösung gefunden!] Lösung von Friedrich Burchard & Friedrich Hariuc (1976) in 96 Halbzügen NN - NN1. e4 f5…
R B I T. INTERNATIONAL CHESS COMPOSITION MAGAZINE ...docplayer.net › R-b-i-t-international-ches...
docplayer.net
Comm. no.f5 Comm. no.f18 Comm. no.f23 Chris Feather Friedrich Hariuc Valerio Agostini & Antonio Garofalo cuuuuuuuuc cuuuuuuuuc cuuuuuuuuc {wdwdwdwd} ...
Shortest possible game with 18 queens? - Chess Stack Exchangechess.stackexchange.com › questions › shortest-poss...
chess.stackexchange.com
Solution by Friedrich Burchard & Friedrich Hariuc (1976) in 96 Half-moves [FEN ""] 1.e4 f5 2.e5 Nf6 3.exf6 e5 4.g4 e4 5.Ne2 e3 6.
June – Julia's Fairies
juliasfairies.com
Dedicated to Friedrich Hariuc. (18.06) No.1085, – Erich Bartel. No (h==3; Grasshopper; PWC; Madrasi RI); No (ser-s#19; Fers; ...
english g 21 a5 l%C3%B6sungen pdf
test.comentapanel.cl
21, D Mitarbeiter Thomas Brand, Chris Feather, Andrej Frolkin, Friedrich Hariuc, Stefan Höning, ... as well as ...
MICHAEL EHN HUGO KASTNER. Die besten Aufgaben und Komponisten der...
docplayer.org
Probleme Permanente Einengung Friedrich Hariuc # Sie sollten sich nicht gleich von der Ankündigung Matt in 16 ins Bockshorn jagen lassen.
feenschach-informalturnier Hilfsmatt in 3 und mehr Zügen...
docplayer.org
Stefan Parzuch Legionowo H#2 b) f4 h3 C Friedrich Hariuc Duisburg! H#2 2.1;1.1 C Aleksandar Popovski Skopje # H#2 2.1;1.1 C Gerald Ettl München ...
puzzles रानियों के साथ सबसे कम संभव खेल? - While-Do
de-vraag.com
यह प्रश्न का चयनित उत्तर एक ऐसा गेम दिखाता है जिसमें सभी 16 पंजे रानियों को बढ़ावा देते हैं ताकि कुल मिलाकर बोर्ड पर 18 रानियां। इसमें 80 चालें होती हैं...
problems - What is the shortest possible game with 18 queens? - Chess...
chess.stackexchange.com
Solution by Friedrich Burchard & Friedrich Hariuc (1976) in 96 Half-moves. NN - NN. 1. e4 f5 2. e5 Nf6 3. exf6 e5 4. g4 e4 5. Ne2 e3 6. Ng3 e2 7. h4 f4 8. h5 fxg3 ...
Ladies' Night - Futility Closet
www.futilitycloset.com
Yes — Freidrich Burchard of Germany and Friedrich Hariuc of Romania reached nearly identical solutions in 1980: 1. e4 f5 2. e5 Nf6 3. exf6 e5 4. g4 e4 5.
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